iargc(3F)                                               iargc(3F)



NAME
     iargc - return command line arguments

SYNOPSIS
     integer i
     i=iargc()

DESCRIPTION
     The iargc function returns the number of command line
     arguments passed to the program.  Thus, if a program were
     invoked via

          foo arg1 arg2 arg3

     iargc() would return 3.

SEE ALSO
     getarg(3F)





































January 1992                                                    1