iargc(3F)                                               iargc(3F)



     NAME
          iargc - return command line arguments

     SYNOPSIS
          integer i
          i=iargc()

     DESCRIPTION
          The iargc function returns the number of command line argu-
          ments passed to the program.  Thus, if a program were in-
          voked via

               foo arg1 arg2 arg3

          iargc() would return ``3''.

     SEE ALSO
          getarg(3F).





































     April, 1990                                                     1