iargc(3F)                                               iargc(3F)



     NAME
          iargc

     SYNOPSIS
          integer i
          i = iargc()

     DESCRIPTION
          The iargc function returns the number of command line
          arguments passed to the program.  Thus, if a program were
          invoked via

               foo arg1 arg2 arg3

          iargc() would return ``3''.

     SEE ALSO
          getarg(3F).





































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